3[b+1]-5=3b-2

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Solution for 3[b+1]-5=3b-2 equation: 


Simplifying
3[b + 1] + -5 = 3b + -2

Reorder the terms:
3[1 + b] + -5 = 3b + -2
[1 * 3 + b * 3] + -5 = 3b + -2
[3 + 3b] + -5 = 3b + -2

Reorder the terms:
3 + -5 + 3b = 3b + -2

Combine like terms: 3 + -5 = -2
-2 + 3b = 3b + -2

Reorder the terms:
-2 + 3b = -2 + 3b

Add '2' to each side of the equation.
-2 + 2 + 3b = -2 + 2 + 3b

Combine like terms: -2 + 2 = 0
0 + 3b = -2 + 2 + 3b
3b = -2 + 2 + 3b

Combine like terms: -2 + 2 = 0
3b = 0 + 3b
3b = 3b

Add '-3b' to each side of the equation.
3b + -3b = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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